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Day 45 MCAT Practice Question

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Passage 7: Sound

Sound is critically important in marine ecosystems as a method of communication

for animals, submarines, and other technological instruments. Researchers

conducted an experiment to study sound waves in various aquatic contexts, with a

special focus on the speed of sound across varying media.



A speaker emitting high-frequency sound was utilized to generate sound waves at

a fixed frequency. Hydrophones, strategically placed at varying distances from the

radio, measured sound intensity and speed in freshwater, salt water, and air.

The first phase of experimental data collection involved measuring the speed of

sound in these three media at the same temperature. Results showed that there

was a significant difference between all three, with the most significant difference

between either water medium and air. Next, researchers varied the temperature

and salinity of the water in the tanks, measuring the speed of sound at regular

increments.



They also used ultrasound waves to map the seafloor, detecting obstacles. Findings

are tabulated in Table 1:

Attenuation in signal intensity was attributed to absorption and scattering of waves

in the water (as signal intensity decreased with increasing depth). Background noise

in the water column affected the precision of the measurements; regions with high

biological activity reduced measurement accuracy.
Considering a reaction with the following two elementary steps:

Step 1: A2 → 2A (fast)

Step 2: A + B → AB (slow)

Identify the correct rate law for the overall reaction.

A) Rate = k[A2][B]

B) Rate = k[A2]

C) Rate = k[A2]2

D) Rate = k[A][B
Click to reveal answer
Correct answer: A. Since the slow step is rate-determining, the rate

law must be based on step 2. This yields a preliminary rate law of k = [A][B], but A is

an intermediate in this reaction, so we must derive an expression using reactants in

the overall reaction (A2 + B → 2AB) to find the rate law for the overall reaction. Let’s

find a way to substitute A for A2 (a reactant of the overall equation):

From step 1: A2 → 2A. At equilibrium, the concentration of A is proportional to the

concentration of A2: [A] = 2[A2]. Substituting into the rate law for Step 2 yields:

Rate = k[2A2][B] = 2k[A2][B]

Since the rate constant “k” can simply be multiplied by 2 to simplify the equation,

we can simplify the rate law as follows:

Rate = k[A2][B]
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