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Day 43 MCAT Practice Question

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Passage 7: Sound

Sound is critically important in marine ecosystems as a method of communication

for animals, submarines, and other technological instruments. Researchers

conducted an experiment to study sound waves in various aquatic contexts, with a

special focus on the speed of sound across varying media.



A speaker emitting high-frequency sound was utilized to generate sound waves at

a fixed frequency. Hydrophones, strategically placed at varying distances from the

radio, measured sound intensity and speed in freshwater, salt water, and air.

The first phase of experimental data collection involved measuring the speed of

sound in these three media at the same temperature. Results showed that there

was a significant difference between all three, with the most significant difference

between either water medium and air. Next, researchers varied the temperature

and salinity of the water in the tanks, measuring the speed of sound at regular

increments.



They also used ultrasound waves to map the seafloor, detecting obstacles. Findings

are tabulated in Table 1:

Attenuation in signal intensity was attributed to absorption and scattering of waves

in the water (as signal intensity decreased with increasing depth). Background noise

in the water column affected the precision of the measurements; regions with high

biological activity reduced measurement accuracy.
If 40g of ammonium nitrate is heated, how many grams of dinitrogen monoxide

and water vapor will be produced? (Molar masses: NH4NO3 = 80 g/mol, N2O =

44 g/mol, H2O = 18 g/mol)

A) 11g of N2O and 36g of H2O

B) 22g of N2O and 18g of H2O

C) 22g of N2O and 36g of H2O

D) 44g of N2O and 18g of H2O
Click to reveal answer
Correct answer: B. First, we must determine the balanced chemical

equation for the decomposition of ammonium nitrate into dinitrogen monoxide and

water vapor. This comes out to NH4NO3 → N2O + 2H2O. Next, we must determine

how many moles of ammonium nitrate are in the heated 40g sample, which is 40g/

(80g/mol) = 0.5 moles ammonium nitrate. Stoichiometrically, this means that 0.5

moles of dinitrogen monoxide and 1 mole of water vapor will be produced during

this decomposition per the balanced equation. Multiplying both of these molar

quantities by their respective molar masses gives us 22g of N2O and 18g of H2O.
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