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Day 37 MCAT Practice Question

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Passage 6: Soap

Soap bubbles, despite their delicate and transient nature, have fascinated scientists

and laypeople alike for hundreds of years. When passing a white light source

through a soap bubble, a series of colorful bands can be observed along the surface

which changes with thickness of the soap film.

Scientists studying this phenomenon came up with an experiment to investigate

this behavior of light and physical properties of the soap bubbles themselves.



Materials:

• Soap solution

• White light source

• Camera with infrared, visible, and UV filters

• Spectrometer

• Polarizing filters



Procedure:

First, a soap solution was prepared with water, a small amount of soap, and glycerin.

The presence of glycerin was helpful to counter a primary limiting factor for the

stability of soap bubbles: surface tension. The bubbles were then illuminated with

the white light source, and the infrared, visible, and UV camera filters were used to

capture images of the three spectra.



Interference patterns were recorded as the bubbles expanded. Spectrometry was

utilized to analyze the light that was both reflected and transmitted through the film

at different angles. Results are tabulated below.

By the end of the experiment, the researchers concluded that the interference

patterns had the most observable effect on the vibrance of colors in the visible

spectrum. Infrared radiation was largely absorbed, but UV light experienced

significant scattering. When viewed through the polarizing filters, intensity of light

varied consistently with the orientation of the polarizer.
What is the wavelength of light traveling at a speed of 62 x 105

meters/sec with

a frequency of 50 Hz?

A) 6200 meters

B) 62,000 meters

C) 124,000 meters

D) 248,000 meters
Click to reveal answer
Correct answer is C

The speed of light can be calculated using the equation c = νλ, where c = the speed

of light in meters per second, v = the light frequency (units = Hertz or s-

¹), and λ =

wavelength of the light in meters.

Here, c = νλ

62 x 105 meters/sec = 50 s-

¹ (λ)

124,000 meters = λ

For this reason, Answer C is correct and Answers A, B, and D are incorrect.
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