Passage 5: Ribose
Ribose (C5H10O5) is biologically important as the pentose component of
ribonucleotides. It primarily exists in its aldose form, making it highly reactive in
oxidative and reductive conditions.
Ribose’s oxidation to ribonic acid and reduction to ribitol are widely known
transformations of this pentose. In bromine water (Br2 and H2O), ribose is converted
to ribonic acid, and in the presence of sodium borohydride (NaBH4), ribose is
converted to ribitol.
Experiment 1:
Researchers performed the following reactions with ribose under controlled conditions:
Reaction 1:
Ribose + Br2 + H2O → Ribonic acid + 2HBr
Reaction 2:
Ribose + NaBH4 + H2O → Ribitol + NaBO2
Observations:
Following these procedures, the researchers used pH indicators and TLC to monitor
reaction progress/success.
Experiment 2:
In order to map cellular processes that synthesize purines and pyrimidines, ribose
was converted to 5-phosphoribosyl-1-pyrophosphate (PRPP), a precursor for these
nitrogenous bases. This intermediate was then used to synthesize a compound that
is structurally similar to xanthine, a derivative of a purine:
Reaction 3:
Ribose-5-Phosphate + ATP → PRPP + AMP
Reaction 4:
PRPP + Amine → Xanthine Derivative
Experiment 3:
In an effort to further explore the reactivity of xanthine derivatives and extrapolate
to biological systems and biochemical reactions, they used their synthesized
xanthine derivative and reacted with alcohol to form an ether. Reaction progress
was monitored via TLC and confirmation of desired product was determined via
NMR. UV-Vis spectroscopy was conducted before NMR to ensure that a chemical
reaction had indeed occurred, because the former analytical technique is
significantly less expensive.
The researchers performing the experiments in the passage (Group A) forgot to
label the test tubes containing their reagents and products. Another group of
researchers (Group B) working in the same lab was conducting spectroscopic
analysis on derivatives of amino acids, and also forgot to label their test tubes.
Which pair of amino acids, if mixed with Group A’s test tubes, would be the
most difficult to distinguish from the products outlined in the passage via UVVis spectroscopy?
A) F and W
B) T and H
C) D and E
D) A and L
Correct answer: A. The passage states that xanthine is chemically
similar to purines, which are aromatic heterocycles. Thus, xanthine must have
conjugated pi bonds, and might have a similar UV-Vis spectrum to phenylalanine
and tryptophan (especially tryptophan) and would be harder to distinguish from
them using this technique. The other answer choices involve amino acids which do
not have distinct UV-Vis spectra.