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Day 29 MCAT Practice Question

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Passage 5: Ribose

Ribose (C5H10O5) is biologically important as the pentose component of

ribonucleotides. It primarily exists in its aldose form, making it highly reactive in

oxidative and reductive conditions.

Ribose’s oxidation to ribonic acid and reduction to ribitol are widely known

transformations of this pentose. In bromine water (Br2 and H2O), ribose is converted

to ribonic acid, and in the presence of sodium borohydride (NaBH4), ribose is

converted to ribitol.

Experiment 1:

Researchers performed the following reactions with ribose under controlled conditions:

Reaction 1:

Ribose + Br2 + H2O → Ribonic acid + 2HBr

Reaction 2:

Ribose + NaBH4 + H2O → Ribitol + NaBO2

Observations:

Following these procedures, the researchers used pH indicators and TLC to monitor

reaction progress/success.

Experiment 2:

In order to map cellular processes that synthesize purines and pyrimidines, ribose

was converted to 5-phosphoribosyl-1-pyrophosphate (PRPP), a precursor for these

nitrogenous bases. This intermediate was then used to synthesize a compound that

is structurally similar to xanthine, a derivative of a purine:

Reaction 3:

Ribose-5-Phosphate + ATP → PRPP + AMP

Reaction 4:

PRPP + Amine → Xanthine Derivative

Experiment 3:

In an effort to further explore the reactivity of xanthine derivatives and extrapolate

to biological systems and biochemical reactions, they used their synthesized

xanthine derivative and reacted with alcohol to form an ether. Reaction progress

was monitored via TLC and confirmation of desired product was determined via

NMR. UV-Vis spectroscopy was conducted before NMR to ensure that a chemical

reaction had indeed occurred, because the former analytical technique is

significantly less expensive.
How do you expect the IR results for ribose to change when placed under

oxidative conditions described in the passage?

A) A strong absorption peak would shift from 1725 cm-1 to 1700 cm-1 under

oxidative conditions. A broad stretch between 3200 cm-1 to 3500 cm-1

would still be observed in both conditions

B) A strong absorption peak would shift from 1650 cm-1 to 2100 cm-1. An

initially observed broad stretch would disappear under oxidative conditions

C) A weak stretch around 1725 cm-1 would shift to 1700 cm-1 under oxidative

conditions. A broad stretch between 3200 cm-1 to 3500 cm-1 would still

be observed in both conditions

D) A strong absorption peak would shift from 1725 cm-1 to 1600cm-1 under

oxidative conditions. The broad stretch between 3200 cm-1 to 3500 cm-1

would disappear under oxidative conditions
Click to reveal answer
Correct answer: A. Aldehydes (such as ribose) display a strong

absorption peak around 1725 cm-1, while carboxylic acids (such as ribonic acid, the

product of placing ribose in oxidative conditions) have a strong absorption peak

around 1700 cm-1. Both groups still have an alcohol group, so the broad stretch

from 3200 cm-1 to 3500 cm-1 should be conserved. The aldehyde C=O stretch

shifts to a slightly lower frequency upon oxidation to a carboxylic acid due to

increased conjugation and resonance stabilization.
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