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Day 26 MCAT Practice Question

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Passage 5: Ribose

Ribose (C5H10O5) is biologically important as the pentose component of

ribonucleotides. It primarily exists in its aldose form, making it highly reactive in

oxidative and reductive conditions.

Ribose’s oxidation to ribonic acid and reduction to ribitol are widely known

transformations of this pentose. In bromine water (Br2 and H2O), ribose is converted

to ribonic acid, and in the presence of sodium borohydride (NaBH4), ribose is

converted to ribitol.

Experiment 1:

Researchers performed the following reactions with ribose under controlled conditions:

Reaction 1:

Ribose + Br2 + H2O → Ribonic acid + 2HBr

Reaction 2:

Ribose + NaBH4 + H2O → Ribitol + NaBO2

Observations:

Following these procedures, the researchers used pH indicators and TLC to monitor

reaction progress/success.

Experiment 2:

In order to map cellular processes that synthesize purines and pyrimidines, ribose

was converted to 5-phosphoribosyl-1-pyrophosphate (PRPP), a precursor for these

nitrogenous bases. This intermediate was then used to synthesize a compound that

is structurally similar to xanthine, a derivative of a purine:

Reaction 3:

Ribose-5-Phosphate + ATP → PRPP + AMP

Reaction 4:

PRPP + Amine → Xanthine Derivative

Experiment 3:

In an effort to further explore the reactivity of xanthine derivatives and extrapolate

to biological systems and biochemical reactions, they used their synthesized

xanthine derivative and reacted with alcohol to form an ether. Reaction progress

was monitored via TLC and confirmation of desired product was determined via

NMR. UV-Vis spectroscopy was conducted before NMR to ensure that a chemical

reaction had indeed occurred, because the former analytical technique is

significantly less expensive.
How many chiral centers does ribose have, and how does this change during

the conversion to ribitol?

A) 3; formation of ribitol introduces a new chiral center

B) 4; formation of ribitol does not change the number of chiral centers

C) 3; formation of ribitol reduces the number of chiral centers by 1

D) 4; formation of ribitol introduces a new chiral center
Click to reveal answer
Correct answer: C. Ribose has 3 chiral centers (carbons 2, 3, and

4) because these three carbons are each bonded to four different substituents.

However, reduction of the aldehyde group of carbon 1 creates an internal plane of

symmetry, removing carbon 3’s chirality. A breakdown of each carbon’s substituents

is as follows:

Carbon 1: (CHO) This carbon is part of an aldehyde group (sp2 hybridized) and

cannot be chiral.

Carbon 2: (CHOH) This is attached to four different groups (hydrogen, hydroxyl,

CH2OH, and CHOH), making it a chiral center.

Carbon 3: (CHOH) This carbon is attached to four different groups (hydrogen

hydroxyl, CHOH, and CHOH), making it a chiral center. Note that the two CHOH

groups that carbon 3 is bonded to are different due to being on opposite halves

of the molecule that are different (the end that includes Carbon 1 has an aldehyde

group, while carbon 5 is an alcohol).

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Carbon 4 (CHOH) This carbon is attached to four different groups as well (hydrogen,

hydroxyl, CHOH, and CH2OH), meeting criteria for chirality.

Carbon 5: (CH2OH) This carbon is bonded to two hydrogen atoms (which are the

same) and cannot meet criteria for chirality.

Due to this, ribose has 3 chiral centers.

Ribitol:

Carbon 1: (CH2OH) This is attached to two hydrogen atoms, and therefore cannot

meet criteria for chirality.

Carbon 2: (CHOH) This is attached to four different groups (hydrogen, hydroxyl,

CH2OH, and CHOH), making it a chiral center.

Carbon 3: (CHOH) Two of this carbon’s groups are identical after reduction of the

aldehyde (hydrogen hydroxyl, CHOH, and CHOH), making it achiral. Note that the

two CHOH groups that carbon 3 is bonded to are chemically the same due to being

on opposite halves of the pentose that are identical (the end that includes Carbon 1

which is now an alcohol is identical to carbon 5’s half).

Carbon 4 (CHOH) This carbon is attached to four different groups (hydrogen,

hydroxyl, CHOH, and CH2OH), meeting criteria for chirality.

Carbon 5: (CH2OH) This carbon is bonded to two hydrogen atoms (which are the

same) and cannot meet criteria for chirality.

Therefore, ribitol has 2 chiral centers, so conversion of ribose to ribitol reduces the

number of chiral centers by 1.
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